-0,5x^2+5x=0

Solution for -0,5x^2+5x=0 equation:

-0.5x^2+5x=0

a = -0.5; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-0.5)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-0.5}=\frac{-10}{-1}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-0.5}=\frac{0}{-1}
=0
$